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8x^2-4=7x
We move all terms to the left:
8x^2-4-(7x)=0
a = 8; b = -7; c = -4;
Δ = b2-4ac
Δ = -72-4·8·(-4)
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{177}}{2*8}=\frac{7-\sqrt{177}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{177}}{2*8}=\frac{7+\sqrt{177}}{16} $
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